Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 1.0 × 10^{−7} m^{2} carrying a current of 1.5 A. Assume the density of conduction electrons to be 9 × 10^{28} m^{−3}

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#### Solution

We know that drift velocity,

`V_d=I/(nAq)`

where *I* is the current, *n* is charge density,* q* is charge of electron and *A* is cross-section area.

`V_d=1.5/(9xx10^28xx1.0xx10^(-7)xx1.6xx10^(-19))`

`V_d=10.4xx10^(-4) "m/s"`

Concept: Drift of Electrons and the Origin of Resistivity

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