The answer is 4

Lets put them into equations

43 = D*q1 + r1;

91 = D*q2 + r2;

183 = D*q3 + r3;

and r1=r2=r3=r

so.

D*(q2-q1)= 48

D*(q3-q2)= 92

D*(q3-q1)= 140

For the greatest value of D take the HCF of 48, 92 and 140 which is 4.

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Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

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